document.write( "Question 1205027: Hi
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document.write( "Mary and Gary had some stickers in the ratio of 5 to 3 respectively. After mary had given 1/3 of her stickers to Gary the new ratio of Gary to Mary became 7 to 5. If Gary had 32 more stickers than Mary what was the combined total.\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #841629 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "This would be a much more interesting problem, open to a large number of different solution methods, if it asked us to find the number of stickers each of them had at the beginning. \n" ); document.write( "However, since the problem only asked for the total number of stickers, there seems to be one path to the solution that is by far the easiest. \n" ); document.write( "After Mary gave 1/3 of her stickers to Gary, the ratio of Gary to Mary was 7:5 and Gary had 32 more stickers than Mary. Given that ratio 7:5... \n" ); document.write( "Let 7x = Gary's stickers \n" ); document.write( "Let 5x = Mary's stickers \n" ); document.write( "(That is one standard way of setting up a problem when a ratio is given; whatever value x has, the ratio 7x:5x is always 7:5.) \n" ); document.write( "Gary had 32 more stickers than Mary: \n" ); document.write( "7x-5x=32 \n" ); document.write( "2x=32 \n" ); document.write( "x=16 \n" ); document.write( "And the total numer of stickers was 7x+5x = 12x = 192. \n" ); document.write( "ANSWER: 192 \n" ); document.write( " \n" ); document.write( " |