document.write( "Question 1205030: Given 30-60-90 triangle with sides p\sqrt(6) , p\sqrt(2 ), q\sqrt(3); find p, q
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Algebra.Com's Answer #841626 by greenestamps(13215)\"\" \"About 
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\n" ); document.write( "Don't use \"\\" -- it might have a special meaning in some area(s) of mathematics.

\n" ); document.write( "I assume the side lengths are p/sqrt(6), q/sqrt(3), and p/sqrt(2).

\n" ); document.write( "The squares of the side lengths are then p^2/6, q^2/3, and p^2/2.

\n" ); document.write( "On first glance, with the denominators 6, 3, and 2, I immediately see that, if p and q are both equal to the same number x, then I have x^2/6+x^2/3=x^2/2, which is true for all values of x.

\n" ); document.write( "So the problem has an infinite number of solutions in which p=q.

\n" ); document.write( "But there might be other solutions hiding somewhere, so lets' look at the problem more closely.

\n" ); document.write( "We know that p/sqrt(2) is greater than p/sqrt(6); but q/sqrt(3) could be less than or greater than p/sqrt(2). So there are two cases to consider: the longest side (hypotenuse) can be either p/sqrt(2) or q/sqrt(3).

\n" ); document.write( "Case 1: the hypotenuse is p/sqrt(2)

\n" ); document.write( "(Note this is the case discussed informally above.)

\n" ); document.write( "\"%28p%2Fsqrt%286%29%29%5E2%2B%28q%2Fsqrt%283%29%29%5E2=%28p%2Fsqrt%282%29%29%5E2\"
\n" ); document.write( "\"p%5E2%2F6%2Bq%5E2%2F3=p%5E2%2F2\"
\n" ); document.write( "\"p%5E2%2B2q%5E2=3p%5E2\"
\n" ); document.write( "\"2q%5E2=2p%5E2\"
\n" ); document.write( "\"p%5E2=q%5E2\"
\n" ); document.write( "\"p=q\"

\n" ); document.write( "Case 2: The hypotenuse is q/sqrt(3)

\n" ); document.write( "\"%28p%2Fsqrt%282%29%29%5E2%2B%28p%2Fsqrt%286%29%29%5E2=%28q%2Fsqrt%283%29%29%5E2\"
\n" ); document.write( "\"p%5E2%2F2%2Bp%5E2%2F6=q%5E2%2F3\"
\n" ); document.write( "\"3p%5E2%2Bp%5E2=2q%5E2\"
\n" ); document.write( "\"4p%5E2=2q%5E2\"
\n" ); document.write( "\"2p%5E2=q%5E2\"
\n" ); document.write( "\"p%2Asqrt%282%29=q\"

\n" ); document.write( "This case also has an infinite number of solutions, where p is any number x and q is x*sqrt(2).

\n" ); document.write( "ANSWER:
\n" ); document.write( "p = any number;
\n" ); document.write( "q = p OR q=p*sqrt(2)

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