document.write( "Question 1205014: On commencing employment a man is paid a salary of GH&7,200 per annum and receives annual increments of
\n" ); document.write( "GH&350. Determine his salary in the 9th year and calculate the total salary he will receive in the first 12 years
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Algebra.Com's Answer #841620 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The amounts of his pay in the different years increase by a constant amount, so they form an arithmetic sequence. The first term is 7200 and the constant difference is 350.

\n" ); document.write( "His salary in the n-th year is his beginning salary, increased by the common difference (n-1) times:

\n" ); document.write( "\"P%28n%29=7200%2B%28n-1%29350\"

\n" ); document.write( "So his salary in the 9th year is

\n" ); document.write( "\"P%289%29=7200%2B8%28350%29=7200%2B2800=10000\"

\n" ); document.write( "In an arithmetic sequence, the sum of n terms is the number of terms, multiplied by the average of the first and last terms. To find his total salary in the first 12 years, the number of terms is 12;the first term is 7200, and we need to find the last (12th) term.

\n" ); document.write( "\"P%2812%29=7200%2B11%28350%29=7200%2B3850=11050\"

\n" ); document.write( "The average of his salaries in the 1st and 12th years is then

\n" ); document.write( "\"%287200%2B11050%29%2F2=9125\"

\n" ); document.write( "And his total salary for his first 12 years is

\n" ); document.write( "\"12%289125%29=109500\"

\n" ); document.write( "ANSWERS:
\n" ); document.write( "9th year: 10,000
\n" ); document.write( "first 12 years: 109,500

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