document.write( "Question 1205022: Mark spent 1/10 of his salary on transport and 1/5 of it on food. He also gave 1/2 of his salary to his parents. He saved the remaining $480.
\n" ); document.write( "a) What fraction of the salary did he save?
\n" ); document.write( "b) How much money did he give his parents?
\n" ); document.write( "c) How much did he spend on food and transport?\r
\n" ); document.write( "\n" ); document.write( "A. a) 1/3, b) $1,000, c) $220\r
\n" ); document.write( "\n" ); document.write( "B. a) 1/5, b) $1,200, c) $240\r
\n" ); document.write( "\n" ); document.write( "C. a) 1/7, b) $1,400, c) $260\r
\n" ); document.write( "\n" ); document.write( "D. a) 1/9, b), $1,600, c) $280
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Algebra.Com's Answer #841605 by Theo(13342)\"\" \"About 
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he spent 1/10 on transport
\n" ); document.write( "he spent 1/5 on food
\n" ); document.write( "he spent 1/2 on his parents
\n" ); document.write( "that's a total of 1/10 + 2/10 + 5/10 = 8/10.
\n" ); document.write( "let x = his total salary.
\n" ); document.write( "he saved 480.
\n" ); document.write( "your formula is 1/10 * x + 1/5 * x + 1/2 * x + 480 = x
\n" ); document.write( "this becomes 8/10 * x + 480 = x
\n" ); document.write( "subtract 8/10 * x from both sides of the equation to get:
\n" ); document.write( "480 = 2/10 * x
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = 10/2 * 480 = 2400\r
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\n" ); document.write( "\n" ); document.write( "the fraction of his salary that he saves if 480 / 2400 = .2 which is equal to 1/5.\r
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\n" ); document.write( "\n" ); document.write( "your solution needs to be selection B.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "part a of selection B is correct.
\n" ); document.write( "part b of selection B is correct.\r
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\n" ); document.write( "\n" ); document.write( "part c doesn't look right.
\n" ); document.write( "from the problem statement, he spent 1/10 on transport.
\n" ); document.write( "that would be 240.
\n" ); document.write( "he also spent 1/5 on food.
\n" ); document.write( "that would be 480.
\n" ); document.write( "if part c was only for transport, it would be correct.
\n" ); document.write( "if it's really transport AND food, then it's wrong, because that would be equal to 3/10 * 2400 = 720.\r
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