document.write( "Question 1205010: A solid copper cylindrical bar 10cm long and 3cm in diameter is drawn out into a wire 1mm in diameter.
\n" ); document.write( "a) How long is the wire.
\n" ); document.write( "b) How long would it be if the diameter was ½mm? \n" ); document.write( "

Algebra.Com's Answer #841601 by ikleyn(52847) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "A solid copper cylindrical bar 10cm long and 3cm in diameter is drawn out into a wire 1mm in diameter.
\n" ); document.write( "a) How long is the wire.
\n" ); document.write( "b) How long would it be if the diameter was ½mm?
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "The diameter of the cross-section of the wire is   the diameter of the original cylinder.\r\n" );
document.write( "\r\n" );
document.write( "Hence, the area of the cross section of the wire is   =  of the area of cross-section of the cylinder.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The volume remains the same ---> HENCE, the length of the wire is 900 times 10 cm, or 9000 cm, which is 90 meters.    ANSWER\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Part (a) is solved mentally.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solve part (b) in the same way.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-----------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The lesson to learn from my solution is the Law of mass conservation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );