document.write( "Question 1204989: A population numbers 20,000 organisms initially and grows by 1.1% each year.\r
\n" ); document.write( "\n" ); document.write( "Suppose P represents population, and t the number of years of growth. An exponential model for the population can be written in the form P = a * b^t where a = ? and b = ?.
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Algebra.Com's Answer #841564 by Theo(13342)\"\" \"About 
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exponential equation is P = a * b ^ t
\n" ); document.write( "a would be equal to 20,000
\n" ); document.write( "b would be equal to 1 + .011 = 1.011
\n" ); document.write( "the equation would become P = 20,000 * 1.011 ^ t.
\n" ); document.write( "the equation can be graphed as shown below.\r
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\n" ); document.write( "\n" ); document.write( "in the graph, x takes the place of t.\r
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\n" ); document.write( "\n" ); document.write( "at x = 0, the value is 20,000 * 1.011 ^ 0 = 20,000\r
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\n" ); document.write( "\n" ); document.write( "at x = 1, the value is 20,000 * 1.011 ^ 1 = 20220\r
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\n" ); document.write( "\n" ); document.write( "at x = 10, the value is 20,000 * 1.011 ^ 10 = 22312.157 rounded to 3 decimal places, as in the graph.\r
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\n" ); document.write( "\n" ); document.write( "to create b, you take 1.1% and divide it by 100 to get .011.
\n" ); document.write( "that's the decimal equivalent of 1.1%.
\n" ); document.write( "you then add 1 to it to get 1.011.
\n" ); document.write( "that becomes the growth factor.\r
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\n" ); document.write( "\n" ); document.write( "20,000 * 1.011 is the same as 20,000 + 20,000 * .011.
\n" ); document.write( "factor out the 20,000 and you get 20,000 * (1 + .011) which becomes 20,000 * 1.011.
\n" ); document.write( "for 1 year out, the value becomes 20,000 * 1.011.
\n" ); document.write( "for 2 years out, the value becomes 20,000 * 1.011 * 1.011 which is equal to 20,000 * 1.011^2
\n" ); document.write( "10 years out is 20,000 * 1.011^10\r
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