document.write( "Question 1204973: A rectangular parking lot must have a perimeter of 520 feet and an area of at least 12,000 square feet. Describe the possible lengths of the parking lot. \n" ); document.write( "
Algebra.Com's Answer #841536 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "x = length
\n" ); document.write( "y = width
\n" ); document.write( "each is in feet\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2(length+width) = perimeter of rectangle
\n" ); document.write( "2(x+y) = perimeter of rectangle
\n" ); document.write( "2(x+y) = 520
\n" ); document.write( "x+y = 520/2
\n" ); document.write( "x+y = 260
\n" ); document.write( "y = -x+260\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "length*width = xy = area of the rectangle
\n" ); document.write( "\"area+%3E=+12000\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"xy+%3E=+12000\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%28-x%2B260%29+%3E=+12000\" plug in y = -x+260\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-x%5E2%2B260x+%3E=+12000\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-x%5E2%2B260x-12000+%3E=+0\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Consider the equation
\n" ); document.write( "\"-x%5E2%2B260x-12000+=+0\"
\n" ); document.write( "Use the quadratic formula to solve and you'll find the x intercepts are x = 60 and x = 200\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If \"60+%3C=+x+%3C=+200\", then f(x) = -x^2+260x-12000 is nonnegative and leads back to \"-x%5E2%2B260x-12000+%3E=+0\" being true.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"xy+%3E=+12000\" is only true when \"60+%3C=+x+%3C=+200\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Due to symmetry, the x coordinate of the vertex is located at the midpoint of those roots. So the x coordinate of the vertex happens when x = (60+200)/2 = 260/2 = 130\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "y = -x+260
\n" ); document.write( "y = -130+260
\n" ); document.write( "y = 130
\n" ); document.write( "and
\n" ); document.write( "xy = 130*130 = 16900\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The largest area possible is 16900 sq ft and it happens when we have a rectangle of dimensions x = 130 and y = 130; i.e. a square with side length 130 ft.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Another possible parking lot is when x = 80 and y = 180. It produces an area of xy = 80*180 = 14400 sq ft.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Another possible parking lot is when x = 100 and y = 160. It produces an area of xy = 100*160 = 16000 sq ft.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "There are infinitely many lots we can form. Simply pick any x value in the interval \"60+%3C=+x+%3C=+200\" to find its paired y value.
\n" ); document.write( "Make sure the x and y values add to 260.
\n" ); document.write( "
\n" ); document.write( "
\n" );