document.write( "Question 1204959: Use identities to write the expression as a function of x.\r
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Algebra.Com's Answer #841516 by ikleyn(52908)\"\" \"About 
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document.write( "Use trigonometric identity - the addition formula for tangents\r\n" );
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document.write( "    tan(a+b) = \"%28tan%28a%29%2Btan%28b%29%29%2F%281-tan%28a%29%2Atan%28b%29%29\".    (1)\r\n" );
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document.write( "It gives\r\n" );
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document.write( "    \"tan%28x+%2B+pi%2F6%29\" = \"%28tan%28x%29+%2B+tan%28pi%2F6%29%29%2F%281+-+tan%28x%29%2Atan%28pi%2F6%29%29\".    (2)\r\n" );
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document.write( "Next, use the formula of half-angle for tangents to express  \"tan%28pi%2F6%29\"\r\n" );
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document.write( "    \"tan%28pi%2F6%29\" = \"tan%28%28%28pi%2F3%29%29%2F2%29\" = \"sin%28pi%2F3%29%2F%281%2Bcos%28pi%2F3%29%29%29\" = \"%28%28sqrt%283%29%2F2%29%29%2F%281%2B1%2F2%29\" = \"%28%28sqrt%283%29%2F2%29%29%2F%28%283%2F2%29%29\" = \"sqrt%283%29%2F3\".    (3)\r\n" );
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document.write( "Continue (2)\r\n" );
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document.write( "    \"tan%28x+%2B+pi%2F6%29\" = \"%28tan%28x%29+%2B+tan%28pi%2F6%29%29%2F%281+-+tan%28x%29%2Atan%28pi%2F6%29%29\" = \"%28tan%28x%29+%2B+sqrt%283%29%2F3%29%2F%281-tan%28x%29%2A%28sqrt%283%29%2F3%29%29\" = \"%283%2Atan%28x%29%2Bsqrt%283%29%29%2F%283-sqrt%283%29%2Atan%28x%29%29\".\r\n" );
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document.write( "ANSWER.  \"tan%28x%2Bpi%2F6%29\"  simplified is  \"%283%2Atan%28x%29%2Bsqrt%283%29%29%2F%283-sqrt%283%29%2Atan%28x%29%29\".\r\n" );
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