document.write( "Question 1204947: It is 76°F at the 5,500-foot level of a mountain and 41°F at the 9,000-foot level of the mountain.\r
\n" ); document.write( "\n" ); document.write( "Use the elevation as the e-value. For example, at the elevation 7000 feet, use e=7000.\r
\n" ); document.write( "\n" ); document.write( "a. Write an equation to find the temperature (T) at an elevation (e) on the mountain.
\n" ); document.write( " Round decimals to 4 places.\r
\n" ); document.write( "\n" ); document.write( "b. Using your equation from part (a), predict the temperature at an elevation of 16,200 feet.
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Algebra.Com's Answer #841504 by Alan3354(69443)\"\" \"About 
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It is 76°F at the 5,500-foot level of a mountain and 41°F at the 9,000-foot level of the mountain.
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\n" ); document.write( "The altitude change is 3500 feet and the temperature change is -35 degs.
\n" ); document.write( "---> -1 deg/100 feet
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\n" ); document.write( "\n" ); document.write( "Use the elevation as the e-value. For example, at the elevation 7000 feet, use e=7000.\r
\n" ); document.write( "\n" ); document.write( "a. Write an equation to find the temperature (T) at an elevation (e) on the mountain.
\n" ); document.write( " Round decimals to 4 places.
\n" ); document.write( "\"T+=+76+-+%28e-3500%29%2F100\" degs F
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\n" ); document.write( "\n" ); document.write( "b. Using your equation from part (a), predict the temperature at an elevation of 16,200 feet.
\n" ); document.write( "\"T+=+76+-+%2816200+-+3500%29%2F100\"
\n" ); document.write( "T = -51 degs F
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\n" ); document.write( "This assumes the relation between altitude and temp is linear, but it is not.
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