document.write( "Question 1204941: Convert the given polar equation to a Cartesian equation. (Use the following as necessary: x and y.)
\n" ); document.write( "r = 4 sin(𝜃)
\n" ); document.write( "

Algebra.Com's Answer #841489 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "\"r+=+4sin%28theta%29\"\r
\n" ); document.write( "\n" ); document.write( "we know that:\r
\n" ); document.write( "\n" ); document.write( "\"x=r%2Acos%28theta%29+\" => \"cos%28theta%29=x%2Fr\".....eq.1\r
\n" ); document.write( "\n" ); document.write( "\"y=r%2Asin%28theta%29+\"=>\"sin%28theta%29=y%2Fr\"....eq.2\r
\n" ); document.write( "\n" ); document.write( "\"tan%5E-1%28theta%29=y%2Fx\"....eq.3\r
\n" ); document.write( "\n" ); document.write( "\"r=sqrt%28x%5E2%2By%5E2%29\" => \"r%5E2=x%5E2%2By%5E2\"....eq.4\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "then, substituting \"sin%28theta%29\" from eq.2 given equation becomes\r
\n" ); document.write( "\n" ); document.write( " \"r+=+4%28y%2Fr%29\"......both sides multiply by \"r\"\r
\n" ); document.write( "\n" ); document.write( "\"r%5E2+=+4y\" ....substitute \"r%5E2\" from eq.4\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2By%5E2+=+4y+\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2By%5E2+-4y+=0\" => a Cartesian equation\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );