document.write( "Question 1204873: Given ∠θ in standard position with its terminal arm in the stated quadrant, find the exact values of the remaining five trigonometric ratios for θ.
\n" ); document.write( "cos θ = -2/3, quadrant II
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Algebra.Com's Answer #841409 by MathLover1(20850)\"\" \"About 
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\r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "\"cos%28theta%29=+-2%2F3\", quadrant II\r
\n" ); document.write( "\n" ); document.write( "since \"cos%28theta%29=+adj%2Fhyp\", we know that\r
\n" ); document.write( "\n" ); document.write( "\"adj=-2\"
\n" ); document.write( "\"hyp=3\"\r
\n" ); document.write( "\n" ); document.write( "then
\n" ); document.write( "\"opp=sqrt%283%5E2-%28-2%29%5E2%29\"
\n" ); document.write( "\"opp=sqrt%289-4%29\"
\n" ); document.write( "\"opp=sqrt%285%29\"\r
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\n" ); document.write( "\n" ); document.write( "then\r
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\n" ); document.write( "\n" ); document.write( "\"sin%28theta%29=opp%2Fhyp\"\r
\n" ); document.write( "\n" ); document.write( "\"sin%28theta%29=sqrt%285%29%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "In Quadrant II, ⁡ \"sin%28theta%29\" is positive, so we need \"sin%28theta%29=sqrt%285%29%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"tan%28theta%29=sin%28theta%29%2Fcos%28theta%29\"\r
\n" ); document.write( "\n" ); document.write( "\"tan%28theta%29=%28sqrt%285%29%2F3%29%2F%28-2%2F3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"tan%28theta%29=-sqrt%285%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"cot%28theta%29=cos%28theta%29%2Fsin%28theta%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cot%28theta%29=%28-2%2F3%29%2F%28sqrt%285%29%2F3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cot%28theta%29=-2%2F%28sqrt%285%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cot%28theta%29=-%282sqrt%285%29%29%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "\"sec%28theta%29=1%2Fcos%28theta%29\"\r
\n" ); document.write( "\n" ); document.write( "\"sec%28theta%29=1%2F%28-2%2F3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"sec%28theta%29=-3%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"csc%28theta%29=1%2Fsin%28theta%29\"\r
\n" ); document.write( "\n" ); document.write( "\"csc%28theta%29=1%2F%28sqrt%285%29%2F3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"csc%28theta%29=3%2Fsqrt%285%29\"\r
\n" ); document.write( "\n" ); document.write( "\"csc%28theta%29=3sqrt%285%29%2F5\"\r
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