document.write( "Question 1204869: Lana is the oldest of four sisters. Her youngest sister is half her age. The other two sisters are twins 2 years younger than Lana. When the four sisters' ages are added together, the result is 45. If the youngest sister is n years old, what is n? \n" ); document.write( "
Algebra.Com's Answer #841403 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let n be the age of the youngest. \n" ); document.write( "Then Lana's age is 2n. \n" ); document.write( "Then the age of each of the twins is 2n-2. \n" ); document.write( "The sum of all four ages is 45: \n" ); document.write( "(n)+(2n)+(2n-2)+(2n-2) = 45 \n" ); document.write( "7n-4 = 45 \n" ); document.write( "7n = 49 \n" ); document.write( "n = 7 \n" ); document.write( "ANSWER: The age of the youngest is 7 \n" ); document.write( "CHECK: \n" ); document.write( "youngest: n = 7 \n" ); document.write( "Lana: 2n = 14 \n" ); document.write( "1st twin: 2n-2 = 12 \n" ); document.write( "2nd twin: 2n-2 = 12 \n" ); document.write( "7+14+12+12=45 \n" ); document.write( " \n" ); document.write( " |