document.write( "Question 1204848: At a point A on level ground, the angle of elevation to the top of a shed is 20° . If a person walked 30.0 m away from point A, from the shed, to point B, the angle of elevation decreases by 12°. Find the height of the shed. \n" ); document.write( "
Algebra.Com's Answer #841375 by mananth(16946)\"\" \"About 
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At a point A on level ground, the angle of elevation to the top of a shed is 20° . If a person walked 30.0 m away from point A, from the shed, to point B, the angle of elevation decreases by 12°. Find the height of the shed.\r
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\n" ); document.write( "\n" ); document.write( " the angle of elevation decreases by 12° It becomes 8 deg\r
\n" ); document.write( "\n" ); document.write( "y height of shed
\n" ); document.write( "x distance from shed to point A on ground\r
\n" ); document.write( "\n" ); document.write( "tan 20 = y/x\r
\n" ); document.write( "\n" ); document.write( "tan 8 = y/(x+30)\r
\n" ); document.write( "\n" ); document.write( "\"tan+20%2Ftan+80+=+%28y%2Fx+%29%2F%28y%2F%28x%2B30%29%29\"\\r
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\n" ); document.write( "\n" ); document.write( "\"tan+20%2Ftan+8+=+%28x%2B30%29%2Fx\"\r
\n" ); document.write( "\n" ); document.write( "tan 20 *x = tan 8 *(x+30)\r
\n" ); document.write( "\n" ); document.write( "x tan 20 - xtan8 =30 tan 8\r
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\n" ); document.write( "\n" ); document.write( "x(tan 20-tan 8)= 30 tan 8\r
\n" ); document.write( "\n" ); document.write( "x = 30* tan 8/ (tan 20-tan 8) \r
\n" ); document.write( "\n" ); document.write( "tan 20 = y/x\r
\n" ); document.write( "\n" ); document.write( "y= x*tan 20 deg The height of shed\r
\n" ); document.write( "\n" ); document.write( "Use calculator to evaluate\r
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