document.write( "Question 1204848: At a point A on level ground, the angle of elevation to the top of a shed is 20° . If a person walked 30.0 m away from point A, from the shed, to point B, the angle of elevation decreases by 12°. Find the height of the shed. \n" ); document.write( "
Algebra.Com's Answer #841375 by mananth(16946)![]() ![]() You can put this solution on YOUR website! At a point A on level ground, the angle of elevation to the top of a shed is 20° . If a person walked 30.0 m away from point A, from the shed, to point B, the angle of elevation decreases by 12°. Find the height of the shed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " the angle of elevation decreases by 12° It becomes 8 deg\r \n" ); document.write( "\n" ); document.write( "y height of shed \n" ); document.write( "x distance from shed to point A on ground\r \n" ); document.write( "\n" ); document.write( "tan 20 = y/x\r \n" ); document.write( "\n" ); document.write( "tan 8 = y/(x+30)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "tan 20 *x = tan 8 *(x+30)\r \n" ); document.write( "\n" ); document.write( "x tan 20 - xtan8 =30 tan 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x(tan 20-tan 8)= 30 tan 8\r \n" ); document.write( "\n" ); document.write( "x = 30* tan 8/ (tan 20-tan 8) \r \n" ); document.write( "\n" ); document.write( "tan 20 = y/x\r \n" ); document.write( "\n" ); document.write( "y= x*tan 20 deg The height of shed\r \n" ); document.write( "\n" ); document.write( "Use calculator to evaluate\r \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |