document.write( "Question 1204841: Find the formula of the sequences in terms of n and Tn
\n" ); document.write( "1) 24,12,6,3...
\n" ); document.write( "2) 0,-1/2,-1,-3/2...
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Algebra.Com's Answer #841362 by mananth(16946)\"\" \"About 
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General formula for Tn the nth term in an geometric progression is\r
\n" ); document.write( "\n" ); document.write( "\"tn=+a%2Ar%5E%28n-1%29\"\r
\n" ); document.write( "\n" ); document.write( "where a is the first term and \"r\" is the common ratio and \"n++\" is the number of terms\r
\n" ); document.write( "\n" ); document.write( "1) 24,12,6,3...\r
\n" ); document.write( "\n" ); document.write( "24,12,6,3... the common ratio is 12/24 =6/12 = 6/12 =1/2
\n" ); document.write( "a= 24\r
\n" ); document.write( "\n" ); document.write( "\"tn=+24%2A%281%2F2%29%5E%28n-1%29\"\r
\n" ); document.write( "\n" ); document.write( "2) 0,-1/2,-1,-3/2...\r
\n" ); document.write( "\n" ); document.write( "0,-1/2,-1,-3/2...\r
\n" ); document.write( "\n" ); document.write( "-1/2-0 = -1-(-1/2) = (-3/2)-(-1)= -1/2\r
\n" ); document.write( "\n" ); document.write( "The difference between two consecutive terms is -1/2 = d \r
\n" ); document.write( "\n" ); document.write( "The nth. term of an AP is\r
\n" ); document.write( "\n" ); document.write( "\"tn=+a%2B%28n-1%29%2Ad\" , a is first term and n the number of terms
\n" ); document.write( "a=0 , and d= -1/2\r
\n" ); document.write( "\n" ); document.write( "\"tn+=+0%2B%28n-1%29%2A%28-1%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"tn+=+%28n-1%29%2A%28-1%2F2%29\"\r
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