document.write( "Question 1204841: Find the formula of the sequences in terms of n and Tn
\n" );
document.write( "1) 24,12,6,3...
\n" );
document.write( "2) 0,-1/2,-1,-3/2... \n" );
document.write( "
Algebra.Com's Answer #841362 by mananth(16946)![]() ![]() You can put this solution on YOUR website! General formula for Tn the nth term in an geometric progression is\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "where a is the first term and \n" ); document.write( "\n" ); document.write( "1) 24,12,6,3...\r \n" ); document.write( "\n" ); document.write( "24,12,6,3... the common ratio is 12/24 =6/12 = 6/12 =1/2 \n" ); document.write( "a= 24\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2) 0,-1/2,-1,-3/2...\r \n" ); document.write( "\n" ); document.write( "0,-1/2,-1,-3/2...\r \n" ); document.write( "\n" ); document.write( "-1/2-0 = -1-(-1/2) = (-3/2)-(-1)= -1/2\r \n" ); document.write( "\n" ); document.write( "The difference between two consecutive terms is -1/2 = d \r \n" ); document.write( "\n" ); document.write( "The nth. term of an AP is\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "a=0 , and d= -1/2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |