document.write( "Question 1204835: The sum of age's of a man and his daughter is 120years.six years ago,the man's age was thrice that of his daughter.find their present age.
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Algebra.Com's Answer #841344 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "A typical formal algebraic solution would start with the given information that the sum of the man's age and his daughter's age is 120: \n" ); document.write( "m = man's age \n" ); document.write( "d = daughter's age \n" ); document.write( "m+d=120 \n" ); document.write( "Then the next step would be to write the equation that says six years ago the man was three times as old as his daughter: \n" ); document.write( "m-6 = man's age 6 years ago \n" ); document.write( "d-6 = daughter's age 6 years ago \n" ); document.write( "m-6=3(d-6) \n" ); document.write( "From there some method would be used to solve the system of two equations in m and d to find their current ages. \n" ); document.write( "I leave it to you to follow through with that solution method if you want; it is good algebra practice. \n" ); document.write( "But a different setup for solving the problem, using a single variable, makes solving the problem easier. \n" ); document.write( "Instead of starting with the first piece of given information, start with the second. 6 years ago, the man was three times as old as his daughter: \n" ); document.write( "x = daughter's age 6 years ago \n" ); document.write( "3x = man's age 6 years ago \n" ); document.write( "The sum of their ages now is 120: \n" ); document.write( "x+6 = daughter's age now \n" ); document.write( "3x+6 = man's age now \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWERS: Their ages now are \n" ); document.write( "daughter: x+6 = 27+6 = 33 \n" ); document.write( "man: 3x+6 = 81+6 = 87 \n" ); document.write( " \n" ); document.write( " |