document.write( "Question 1204835: The sum of age's of a man and his daughter is 120years.six years ago,the man's age was thrice that of his daughter.find their present age.
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Algebra.Com's Answer #841344 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "A typical formal algebraic solution would start with the given information that the sum of the man's age and his daughter's age is 120:

\n" ); document.write( "m = man's age
\n" ); document.write( "d = daughter's age
\n" ); document.write( "m+d=120

\n" ); document.write( "Then the next step would be to write the equation that says six years ago the man was three times as old as his daughter:

\n" ); document.write( "m-6 = man's age 6 years ago
\n" ); document.write( "d-6 = daughter's age 6 years ago
\n" ); document.write( "m-6=3(d-6)

\n" ); document.write( "From there some method would be used to solve the system of two equations in m and d to find their current ages.

\n" ); document.write( "I leave it to you to follow through with that solution method if you want; it is good algebra practice.

\n" ); document.write( "But a different setup for solving the problem, using a single variable, makes solving the problem easier.

\n" ); document.write( "Instead of starting with the first piece of given information, start with the second. 6 years ago, the man was three times as old as his daughter:

\n" ); document.write( "x = daughter's age 6 years ago
\n" ); document.write( "3x = man's age 6 years ago

\n" ); document.write( "The sum of their ages now is 120:

\n" ); document.write( "x+6 = daughter's age now
\n" ); document.write( "3x+6 = man's age now
\n" ); document.write( "\"%28x%2B6%29%2B%283x%2B6%29=120\"
\n" ); document.write( "\"4x%2B12=120\"
\n" ); document.write( "\"4x=108\"
\n" ); document.write( "\"x=27\"

\n" ); document.write( "ANSWERS: Their ages now are
\n" ); document.write( "daughter: x+6 = 27+6 = 33
\n" ); document.write( "man: 3x+6 = 81+6 = 87

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