document.write( "Question 1204826: Solve \"7%2F3+=+5%2Fx+%2B4\" for x. \n" ); document.write( "
Algebra.Com's Answer #841335 by ikleyn(52777)\"\" \"About 
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document.write( "    \"7%2F3\" = \"5%2Fx+%2B4\"  implies\r\n" );
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document.write( "    \"7%2F3+-+4\" = \"5%2Fx\"\r\n" );
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document.write( "    \"7%2F3+-+12%2F3\" = \"5%2Fx\"\r\n" );
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document.write( "    \"%287-12%29%2F3\" =\"5%2Fx\"\r\n" );
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document.write( "    \"-5%2F3\" = \"5%2Fx\"\r\n" );
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document.write( "Cancel common factor 5 in both sides  (in other words, divide both sides by 5)\r\n" );
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document.write( "    \"-1%2F3\" = \"1%2Fx\"\r\n" );
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document.write( "From this proportion,  x = -3.    ANSWER\r\n" );
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