document.write( "Question 1204800: One acetic acid solution is 70% water and another is 30% water. How many liters of each solution should be mixed to produce 20 liters of a solution that is 60% water? Solve using system of equations \n" ); document.write( "
Algebra.Com's Answer #841304 by mananth(16946)\"\" \"About 
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One acetic acid solution is 70% water and another is 30% water. How many liters of each solution should be mixed to produce 20 liters of a solution that is 60% water? Solve using system of equations \r
\n" ); document.write( "\n" ); document.write( "One acetic acid solution is 70% water let the quantity be x liters
\n" ); document.write( "another is 30% water Let quantity be y liters\r
\n" ); document.write( "\n" ); document.write( "We need 20 liters of acid in final mix
\n" ); document.write( "x+y=20-----------------------(1)\r
\n" ); document.write( "\n" ); document.write( "water percentage equation. 60% water in 20 liters= 12 liters\r
\n" ); document.write( "\n" ); document.write( "0.7x+0.3y= 12-----------------------(2)
\n" ); document.write( "multiply by 10
\n" ); document.write( "7x+3y= 120
\n" ); document.write( "3x+3y=60 (1) multiplied by 3. subtract
\n" ); document.write( "4x=60
\n" ); document.write( "x=15
\n" ); document.write( "Therefore y=5
\n" ); document.write( "Check\r
\n" ); document.write( "\n" ); document.write( " 15+5=20\r
\n" ); document.write( "\n" ); document.write( "0.7*15+5*0.3= 12\r
\n" ); document.write( "\n" ); document.write( "15 liters of the 70% water acid and 5 liters of the 30% water acid are added\r
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