document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1204799>Question 1204799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In making a type of cap, a factory cuts out circles of materials of diameter 35cm. If the circles are cut out of a roll of material 105cm wide and the length of the roll is 20m.<BR>\n" );
document.write( "How many circles can be cut out of the rolls?<BR>\n" );
document.write( "   A roll of the material costs ₦3,000 and other costs involved in making the caps are as follows:<BR>\n" );
document.write( "thread and stiffening ₦3 per cap, labour ₦4 per cap and other costs ₦10 per cap<BR>\n" );
document.write( "What is the cost price per cap?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #841298 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=841298\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 105*2000= 210000\r<BR>\n" );
document.write( "\n" );
document.write( "Area of each circle,   r= 17.5 cm<BR>\n" );
document.write( "Area = pi*(17.5)^2 = 962.1127\r<BR>\n" );
document.write( "\n" );
document.write( "Number of circles = 210000/962.1127 =218circles  \r<BR>\n" );
document.write( "\n" );
document.write( "OR <BR>\n" );
document.write( "105/35 = 3 circles in a column<BR>\n" );
document.write( "2000/35 = 57\r<BR>\n" );
document.write( "\n" );
document.write( "57*3 = 171 \r<BR>\n" );
document.write( "\n" );
document.write( "A roll of the material costs ₦3,000 and other costs involved in making the caps are as follows:<BR>\n" );
document.write( "thread and stiffening ₦3 per cap, labour ₦4 per cap and other costs ₦10 per cap\r<BR>\n" );
document.write( "\n" );
document.write( "218 circles <BR>\n" );
document.write( "material  cost per cap = 3000/218= 13.76 N<BR>\n" );
document.write( "thread and stiffening cost per cap = 3 N<BR>\n" );
document.write( "Labor = 4N<BR>\n" );
document.write( " other costs per cap=  10 N\r<BR>\n" );
document.write( "\n" );
document.write( "Add them up to get the cost per cap\r<BR>\n" );
document.write( "\n" );
document.write( "The cost price per cap, considering material and additional costs, is approximately ₦30.76.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );