document.write( "Question 1204790: The stopping distance s of a car varies directly as the square of its speed v. If a car traveling at 30 mph requires 45 ft to stop, find the stopping distance for a car traveling at 45 mph.
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Algebra.Com's Answer #841290 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The ratio of speeds is 45:30 = 3:2. \n" ); document.write( "Since the stopping distance varies as the square of the speed, the ratio of stopping distances is 3^2:2^2 = 9:4. \n" ); document.write( "ANSWER: 45*(9/4) = 405/4 = 101.25 feet \n" ); document.write( " \n" ); document.write( " |