document.write( "Question 1204790: The stopping distance s of a car varies directly as the square of its speed v. If a car traveling at 30 mph requires 45 ft to stop, find the stopping distance for a car traveling at 45 mph.
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Algebra.Com's Answer #841279 by mananth(16946) $\"\"$ $\"About$

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The stopping distance s of a car varies directly as the square of its speed v. If a car traveling at 30 mph requires 45 ft to stop, find the stopping distance for a car traveling at 45 mph.\r
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\n" ); document.write( "\n" ); document.write( "d= kv^2\r
\n" ); document.write( "\n" ); document.write( "car traveling at 30 mph requires 45 ft to stop, \r
\n" ); document.write( "\n" ); document.write( "45= k*(30)^2\r
\n" ); document.write( "\n" ); document.write( "k= 45/900= 1/20\r
\n" ); document.write( "\n" ); document.write( " stopping distance for a car traveling at 45 mph.\r
\n" ); document.write( "\n" ); document.write( "d=k*v^2\r
\n" ); document.write( "\n" ); document.write( "d = (1/20) * 45^2 \r
\n" ); document.write( "\n" ); document.write( "d=101.25 ft\r
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