document.write( "Question 1204789: Find the perimeter of a right triangle whose hypotenuse is 2 and whose area is 1. \n" ); document.write( "
Algebra.Com's Answer #841277 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( " the area of a right triangle is:\r
\n" ); document.write( "\n" ); document.write( "\"A=%281%2F2%29b%2Aa\" where \"a\" and \"b+\"are legs\r
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\n" ); document.write( "\n" ); document.write( "if hypotenuse is \"c=2\", then\r
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\n" ); document.write( "\n" ); document.write( "\"a=sqrt%282%5E2-b%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"a=sqrt%284-b%5E2%29\"......eq.1\r
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\n" ); document.write( "\n" ); document.write( " if area is \"1\", then\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F2%29b%2Aa+=1\"...substitute\"+a\"\r
\n" ); document.write( "\n" ); document.write( "\"%281%2F2%29b%2Asqrt%284-b%5E2%29+=1\"\r
\n" ); document.write( "\n" ); document.write( "\"b%2Asqrt%284-b%5E2%29+=2\"....square both sides\r
\n" ); document.write( "\n" ); document.write( "\"%28b%2Asqrt%284-b%5E2%29%29%5E2+=2%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2%2A%284-b%5E2%29+=4\"\r
\n" ); document.write( "\n" ); document.write( "\"4b%5E2-b%5E4+-4=0\"\r
\n" ); document.write( "\n" ); document.write( "\"-b%5E4+%2B4b%5E2-4=0\"\r
\n" ); document.write( "\n" ); document.write( "\"-%28b%5E4+-4b%5E2%2B4%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"-%28b%5E4+-2b%5E2-2b%5E2%2B4%29=0\"
\n" ); document.write( "\"-%28%28b%5E4+-2b%5E2%29-%282b%5E2-4%29%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"-%28b%5E2%28b%5E2+-2%29-2%28b%5E2-2%29%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"-%28%28b%5E2+-2%29%28b%5E2-2%29%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "solution\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2-2=0\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=2\"\r
\n" ); document.write( "\n" ); document.write( "\"b=sqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "then \r
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\n" ); document.write( "\n" ); document.write( "\"a=sqrt%284-sqrt%282%29%5E2%29\"......eq.1\r
\n" ); document.write( "\n" ); document.write( "\"a=sqrt%284-2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"a=sqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "perimeter:\r
\n" ); document.write( "\n" ); document.write( "\"P=a%2Bb%2Bc\"\r
\n" ); document.write( "\n" ); document.write( "\"P=sqrt%282%29%2Bsqrt%282%29%2B2\"\r
\n" ); document.write( "\n" ); document.write( "\"P=2sqrt%282%29%2B2\"\r
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