document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1204785>Question 1204785</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2/5 of A's money is equal to 2/3 of B's money, and $48 is the sum of their money.  Determine A and B's amount.\r<BR>\n" );
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document.write( "2/5 of A's = 2/3 of B's.\r<BR>\n" );
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document.write( "1/5 of A's = 1/2 as much as 2/5, and 1/2 of 2/3 = 1/3 of B's.\r<BR>\n" );
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document.write( "Not sure how to proceed. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #841271 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=841271\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Given the fact that 2/5 of A's money is 2/3 of B's money, you had the thought of, in effect, dividing each fraction by 2 to see that 1/5 of A's money is 1/3 of B's money.<br><BR>\n" );
document.write( "That was potentially a good thought; but it didn't lead anywhere that you were able to see.<br><BR>\n" );
document.write( "In fact, one good start on the problem is to MULTIPLY both fractions by some number to make the information easier to work with.  Since the denominators of the fractions are 5 and 3, we can clear fractions if we multiply both of the given fractions by 5*3=15:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%2F5%29A=%282%2F3%29B ALIGN=MIDDLE  ALT=\"%282%2F5%29A=%282%2F3%29B\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6A=10B ALIGN=MIDDLE  ALT=\"6A=10B\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3A=5B ALIGN=MIDDLE  ALT=\"3A=5B\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3A-5B=0 ALIGN=MIDDLE  ALT=\"3A-5B=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "Then, using A+B=48, there are several possible paths to the solution.<br><BR>\n" );
document.write( "A couple of basic algebraic paths are these:<BR>\n" );
document.write( "(1) Change A+B=48 to B=48-A and substitute \"48-A\" for \"B\" in 3A-5B=0<BR>\n" );
document.write( "(2) Use elimination with the two equations A+B=48 and 3A-5B=0<br><BR>\n" );
document.write( "I myself prefer a less obvious path to the solution, like this:<br><BR>\n" );
document.write( "Given 3A = 5B, let A = 5x and B = 3x.<br><BR>\n" );
document.write( "Then A+B=48 becomes<BR>\n" );
document.write( "5x+3x=48<BR>\n" );
document.write( "8x=48<BR>\n" );
document.write( "x=6<br><BR>\n" );
document.write( "and so<br><BR>\n" );
document.write( "ANSWERS: A = 5x = 30; B = 3x = 18<br><BR>\n" );
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