document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1204786>Question 1204786</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2 ^ log(2,(2x + 3)) + 5^log(5,(x + 7)) = 7 ^ log_7(2x + 18) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #841270 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=841270\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 ^ log_2(2x + 3) + 5 ^ log_5(x + 7) = 7 ^ log_7(2x + 18)<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2+%5E+log%282%2C%282x+%2B+3%29%29+%2B+5%5Elog%285%2C%28x+%2B+7%29%29+=+7%5Elog%287%2C%282x+%2B+18%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "2x+3 + (x+7) = 2x+18<BR>\n" );
document.write( "3x + 10 = 2x + 18<BR>\n" );
document.write( "x = 8<BR>\n" );
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