document.write( "Question 1204779: a street light is at the top of a 17ft tall pole. a woman 6ft tall walks away from th epole with a speed of 8ft/sec along a straight path how fast is the tip a shadow moving when she is 40 ft from the base of the pole? \n" ); document.write( "
Algebra.Com's Answer #841262 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "a street light is at the top of a 17ft tall pole. a woman 6ft tall walks away
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document.write( "In this problem, there are two right-angled triangles: one has a 17 ft tall pole as vertical leg;\r\n" );
document.write( "the other has 6 ft tall woman as vertical leg.\r\n" );
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document.write( "The hypotenuse is a straight line from the the pole tip to the woman' shadow tip.\r\n" );
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document.write( "These triangles are similar: they have common acute angle at the tip of the shadow.\r\n" );
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document.write( "From similarity, we can write a proportion\r\n" );
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document.write( "    \"17%2F%28L%2Bd%29\" = \"6%2Fd\",\r\n" );
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document.write( "where L is the current horizontal distance of the woman from the pole and d is the length the shadow.\r\n" );
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document.write( "From this proportion\r\n" );
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document.write( "    17d = 6*(L+d).    (1)\r\n" );
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document.write( "L and d are functions of time: L = L(t),  d = d(t). \r\n" );
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document.write( "Let's differentiate (1) over time t.  You will get\r\n" );
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document.write( "    17*d'(t) = 6*L'(t) + 6*d'(t).   (2)\r\n" );
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document.write( "The derivative L'(t) is the speed of the woman; it is given in the problem, L'(t) = const = 8 ft/s.\r\n" );
document.write( "So, we substitute 8 ft/s instead of L'(t) into (2).  We get then\r\n" );
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document.write( "    17*d'(t) = 6*8 + 6*d'(t)\r\n" );
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document.write( "    17*d'(t) - 6*d'(t)  = 48\r\n" );
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document.write( "    11*d'(t) = 48\r\n" );
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document.write( "    d'(t) = \"48%2F11\" ft/s.\r\n" );
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document.write( "We get an interesting fact: the length of the shadow in this problem,  d(t),  is a LINEAR function of time with the constant rate of change.\r\n" );
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document.write( "The initial length of the shadow at t= 0,  d(0),  is zero; so, we can write  d(t) = \"%2848%2F11%29%2At\" feet.  \r\n" );
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document.write( "The length of the shadow is the linear function d(t) = \"%2848%2F11%29%2At\".\r\n" );
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document.write( "           Ok.  Let's go further.  We are just on the finish line.\r\n" );
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document.write( "In this problem, we need to get the derivative over the time of the sum (L+d), or (L(t) + d(t))' = L'(t) + d'(t).\r\n" );
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document.write( "As we just noticed above,  L'(t) = 8 ft/s, the speed of the woman.  d'(t) = \"48%2F11\";  so, the sum is\r\n" );
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document.write( "            (L(t) + d(t))' = 8 + \"48%2F11\" = 8 + 4\"4%2F11\" = 12\"4%2F11\" ft/s.\r\n" );
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document.write( "ANSWER.  The tip of the shadow moves at the constant speed of 12\"4%2F11\" ft/s.\r\n" );
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\n" ); document.write( "\n" ); document.write( "From this problem/solution, we learned an unexpected fact: the tip of the shadow moves \r
\n" ); document.write( "\n" ); document.write( "at the constant speed, which does not depend on the horizontal distance of the person from the pole.\r
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