document.write( "Question 1204781: Log3(2-x) = 3 \n" ); document.write( "
Algebra.Com's Answer #841261 by Alan3354(69443)\"\" \"About 
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Log3(2-x) = 3
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\n" ); document.write( "If it's
\n" ); document.write( "\"Log%283%282-x%29%29+=+3\" --- base 10, then
\n" ); document.write( "3(2-x) = 10^3 = 1000
\n" ); document.write( "2-x = 1000/3
\n" ); document.write( "x = 2 - (1000/3) = -994/3
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