document.write( "Question 1204775: Find the price that will maximize profit for the demand and cost functions, where p is the price, x is the number of units, and C is the cost.
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\n" ); document.write( "p = 80 − 0.1sqrtx C = 35x + 600
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Algebra.Com's Answer #841250 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"p%28x%29+=+80+-+0.1sqrt%28x%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"C%28x%29+=+35x+%2B+600\"\r
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\n" ); document.write( "\n" ); document.write( "To find the price that will maximize profit, using demand and cost functions, first step is to find the profit function \"P%28x%29\". Then, use the first derivative to find the critical points for the profit function. Finally use the critical points to find the price to maximize profit.\r
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\n" ); document.write( "\n" ); document.write( "Profit Function:\r
\n" ); document.write( "\n" ); document.write( "\"P%28x%29+%29+=+R%28x%29+-+C%28x%29+\"...revenue \"R%28x%29+=x%2Ap%28x%29\"\r
\n" ); document.write( "\n" ); document.write( " \"P%28x%29+%29+=+x%2Ap%28x%29+-+C%28x%29+\"\r
\n" ); document.write( "\n" ); document.write( " \"+P%28x%29+%29+=+x%2A%2880+-+0.1sqrt%28x%29+%29+-+%2835x+%2B+600%29\"
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\n" ); document.write( " \"P%28x%29+=+80x+-+0.1x%5E%283%2F2%29+-+35x+-600+\"\r
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\n" ); document.write( "\n" ); document.write( "Then find first derivate and set equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "\"%28d%2Fdx%29%2880x+-+0.1x%5E%283%2F2%29+-+35x+-600+%29=-0.15+%28sqrt%28x%29+-+300%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-0.15+%28sqrt%28x%29+-+300%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%29+-+300=0\"\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%29+=300\"\r
\n" ); document.write( "\n" ); document.write( "\"x=300%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+90000\"\r
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\n" ); document.write( "\n" ); document.write( " The maximum profit is \"P%2890000%29\"'.
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