document.write( "Question 1204764: At the local drive-in theater, the manager sold 200 tickets. Adult tickets cost $9 each, while children's tickets cost $5 each. If the theater sold $1420 worth of tickets, how many adult tickets and how many children's tickets were sold?\r
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Algebra.Com's Answer #841233 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
a = number of adult tickets
\n" ); document.write( "c = number of child tickets.
\n" ); document.write( "your equations are:
\n" ); document.write( "a + c = 200
\n" ); document.write( "9a + 5c = 1420
\n" ); document.write( "multiply boh sides of the first equation by 9 and leave the second equation as is to get:
\n" ); document.write( "9a + 9c = 1800
\n" ); document.write( "9a + 5c = 1420
\n" ); document.write( "subtract the second equation from the first to get:
\n" ); document.write( "4c = 380
\n" ); document.write( "solve for c to get:
\n" ); document.write( "c = 380/4 = 95
\n" ); document.write( "a = 200 - 95 = 105
\n" ); document.write( "you have 105 adult tickets and 95 child tickets.
\n" ); document.write( "total cost is 9 * 105 + 5 * 95 = 1420.
\n" ); document.write( "numbers look good.
\n" ); document.write( "your solution is 105 adult and 95 child tickets were sold.
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