document.write( "Question 1204760: The length of a rectangle exceeds its width by 4 inches. find the dimensions of the rectangle if the area is 12 square inches \n" ); document.write( "
Algebra.Com's Answer #841229 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "w = width
\n" ); document.write( "w+4 = length\r
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\n" ); document.write( "\n" ); document.write( "width*length = area
\n" ); document.write( "w*(w+4) = 12
\n" ); document.write( "w^2+4w = 12
\n" ); document.write( "w^2+4w-12 = 0\r
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\n" ); document.write( "\n" ); document.write( "Use the quadratic formula to solve for w.
\n" ); document.write( "Or you can guess-and-check to factor.
\n" ); document.write( "Either way you should find that:
\n" ); document.write( "w = -6, w = 2
\n" ); document.write( "Ignore the negative value. A negative width is not possible.\r
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\n" ); document.write( "\n" ); document.write( "If w = 2, then w+4 = 2+4 = 6
\n" ); document.write( "The rectangle is 2 inches by 6 inches.
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