document.write( "Question 1204749: Write the equation for the conic section in standard form and general form.\r
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Algebra.Com's Answer #841210 by Edwin McCravy(20060) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "The horizontal blue line I added:\r\n" );
document.write( "The transverse axis extends from vertex (-7,-3/2) to vertex (-1,-3/2)\r\n" );
document.write( "so the transverse axis is 6 units long. The semi-transverse axis is\r\n" );
document.write( "'a' which is half of 6 or a=3.\r\n" );
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document.write( "The vertical blue line that I added:\r\n" );
document.write( "The conjugate axis extends from midpoint of top side to midpoint of \r\n" );
document.write( "bottom side of defining rectangle, from (4,-1) to vertex (-4,-2)\r\n" );
document.write( "so the conjugate axis is 1 units long. The semi-conjugate axis is\r\n" );
document.write( "'b' which is half of 1 or b=1/2.\r\n" );
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document.write( "The center is (h,k)=(-4,-3/2) so the equation becomes in standard form\r\n" );
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document.write( "Now if you do some work on that, you'll \r\n" );
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document.write( "end up with this general form: \r\n" );
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document.write( "Edwin

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