document.write( "Question 1204728: Please show work
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document.write( "If you mix 143ml of 70% alcohol with 1857ml of distilled water, the result would yield to.
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document.write( "A. 2000ml of 10% alcohol
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document.write( "B. 2L of 10% water
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document.write( "C. 2000ml of 5% water
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document.write( "D. 2000ml of 5% alcohol \n" );
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Algebra.Com's Answer #841175 by Theo(13342) You can put this solution on YOUR website! i believe your answer will be selection D (2000 ml of 5% alcohol.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's how i analyzed it.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have 143 ml of 70% alcohol. \n" ); document.write( "this gives you .7 * 143 = 100.1 ml of alcohol.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you add 143 ml of the solution plus 1857 ml of ewater to get a total solution of 2000 ml.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "of this total solution of 2000 ml, 100.1 ml is alcohol. \n" ); document.write( "the ratio of alcohol to total solution is equal to 100.1 / 2000 = .05005. \n" ); document.write( "multiply this by 100 to get 5.005%. \n" ); document.write( "round this to the nearest percent to get 5%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's why i picked selection D.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |