document.write( "Question 1204726: Find the set of values of x for which
\n" ); document.write( "A . 3(2X+1)>5-2x
\n" ); document.write( "B.2x*2-7X+3>0
\n" ); document.write( "C..BOTH 3(2X+1)>5-2X AND 2X*2-7X+3>0
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Algebra.Com's Answer #841174 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
a.
\n" ); document.write( "3 * (2x + 1) > 5 - 2x
\n" ); document.write( "simplify to get:
\n" ); document.write( "6x + 3 > 5 - 2x
\n" ); document.write( "add 2x to both sides and subtract 3 from both sides to get:
\n" ); document.write( "8x > 2/8 which becomes x > .25.\r
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\n" ); document.write( "\n" ); document.write( "b.
\n" ); document.write( "2x^2 - 7x + 3 > 0
\n" ); document.write( "set it equal to 0 to get:
\n" ); document.write( "2x^2 - 7x + 3 = 0
\n" ); document.write( "factor to get:
\n" ); document.write( "(2x-1) * (x-3) = 0
\n" ); document.write( "zero points are x = .5 and x = 3
\n" ); document.write( "2x^2 - 7x + 3 is less than zero between x = .5 and x = 3.
\n" ); document.write( "it is greater than zero when x is less than .5 and x is greater than 3.\r
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\n" ); document.write( "\n" ); document.write( "to satisfy both inequalities, you hneed to have both x > .25 and x < .5 and x > 3.\r
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\n" ); document.write( "\n" ); document.write( "your solution should be .25 < x < .5 or x > 3.\r
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\n" ); document.write( "\n" ); document.write( "that can be seen in the following graph using desmos.com/calculator.\r
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\n" ); document.write( "\n" ); document.write( "the area on the graph that is not shaded is your region of feasibility.\r
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\n" ); document.write( "\n" ); document.write( "let me know if you have any questions.\r
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\n" ); document.write( "\n" ); document.write( "theo\r
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