document.write( "Question 1204704: For the hyperbola, find the equations of the asymptotes.
\n" ); document.write( "x^2 - 4y^2 - 6x - 8y - 11 = 0\r
\n" ); document.write( "\n" ); document.write( "--------
\n" ); document.write( "After working the equation into standard form and having found the center and vertices, I wrote the equation of the asymptotes as
\n" ); document.write( "y = k +- b/a(x-h) => y = -1 +- 2/4(x-3)\r
\n" ); document.write( "\n" ); document.write( "But the answer I was provided was
\n" ); document.write( "x - 2y - 5 = 0
\n" ); document.write( "x + 2y - 1 = 0\r
\n" ); document.write( "\n" ); document.write( "What is this form?
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Algebra.Com's Answer #841137 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Simplify
\n" ); document.write( "y = -1 + 2/4(x-3) \r
\n" ); document.write( "\n" ); document.write( "y = -1 + 1/2(x-3)
\n" ); document.write( "multiply equation by 2\r
\n" ); document.write( "\n" ); document.write( "2y=-2+x-3
\n" ); document.write( "2y=x-5
\n" ); document.write( "2y-x+5=0
\n" ); document.write( "x-2y-5=0\r
\n" ); document.write( "\n" ); document.write( "y = -1 - 2/4(x-3)
\n" ); document.write( "2y=-2-x+3
\n" ); document.write( "2y= -x+1\r
\n" ); document.write( "\n" ); document.write( "x+2y-1=0
\n" ); document.write( "
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