document.write( "Question 1204698: Determine the equation of the hyperbola in standard form and general form.
\n" ); document.write( "https://i.ibb.co/4jjgzVK/1.jpg\r
\n" ); document.write( "\n" ); document.write( "Answer for the standard equation was ((y + 1)^2)/4 - ((x + 2)^2)/(1/4) = 1\r
\n" ); document.write( "\n" ); document.write( "My answer was of course wrong: ((y + 1)^2)/16 - ((x + 2)^2)/1 = 1
\n" ); document.write( "There was no point in rewriting into general form when my standard form was already incorrect\r
\n" ); document.write( "\n" ); document.write( "What I did:
\n" ); document.write( "Center (-2, -1)
\n" ); document.write( "I picked points (-1, 3) and (-3, 3) on the two asymptotes to find slope +/- 4
\n" ); document.write( "Does that mean a = 4 and b = 1?
\n" ); document.write( "Because that’s what I used to plug into the equation ((y - k)^2)/a^2 - ((x - h)^2)/b^2 = 1
\n" ); document.write( "

Algebra.Com's Answer #841133 by greenestamps(13209)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The slopes of the asymptotes being 4 and -4 does not mean a=4 and b=1. It only means a/b=4.

\n" ); document.write( "The given graph shows the larger y value when x=-2 has to be 1. Use that to find a and then b:

\n" ); document.write( "----------------------------------------------

\n" ); document.write( "(revised presentation, after question from student....)
\n" ); document.write( "\"%28y%2B1%29%5E2%2Fa%5E2-%28x%2B2%29%5E2%2Fb%5E2=1\"

\n" ); document.write( "When x = -2, the y value is 1:

\n" ); document.write( "\"%281%2B1%29%5E2%2Fa%5E2-%28-2%2B2%29%5E2%2Fb%5E2=1\"
\n" ); document.write( "\"%282%29%5E2%2Fa%5E2-%280%29%5E2%2Fb%5E2=1\"
\n" ); document.write( "\"4%2Fa%5E2=1\"
\n" ); document.write( "\"a%5E2=4\"
\n" ); document.write( "\"a=2\"

\n" ); document.write( "Then a/b=4 leads to b=1/2.

\n" ); document.write( "That gives you the correct equation.

\n" ); document.write( "
\n" ); document.write( "
\n" );