document.write( "Question 1204688: Rocco and Biff are two koala bears frolicking in a meadow. Suddenly, a tasty clump of eucalyptus falls to the ground, catching their attention. Biff glances at Rocco, who appears to be 15 m away, then over to the eucalyptus, which appears to be 18 m away. From Biff’s point of view, Rocco and the eucalyptus are separated by an angle of 45°. Rocco’s top running speed is 1.0 m/s, but Biff can run one and a half times as fast. Can Biff beat Rocco to the eucalyptus? State any assumptions you make. \n" ); document.write( "
Algebra.Com's Answer #841114 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "B = Biff's starting location \n" ); document.write( "R = Rocco's starting location \n" ); document.write( "E = eucalyptus location\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distances or side lengths: \n" ); document.write( "EB = 18 meters \n" ); document.write( "BR = 15 meters\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given angle \n" ); document.write( "angle EBR = 45 degrees\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's add a new point A. \n" ); document.write( "This will be placed on segment BR such that segment EA is perpendicular to segment BR. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Point A splits triangle REB into two right triangles EAB and EAR.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Angle ABE = 45 degrees, which leads to angle AEB = 45 degrees as well.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the 45-45-90 triangle template, or the trig ratio cosine, to determine that segment AB = EB/sqrt(2) = 18/sqrt(2) = 12.7279 approximately. \n" ); document.write( "The segment EA will have the same length because triangle EAB is isosceles.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, \n" ); document.write( "AB + AR = BR \n" ); document.write( "12.7279 + AR = 15 \n" ); document.write( "AR = 15 - 12.7279 \n" ); document.write( "AR = 2.2721 approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Focus your attention on triangle EAR. \n" ); document.write( "It is a right triangle with these approximate leg lengths \n" ); document.write( "EA = 12.7279 \n" ); document.write( "AR = 2.2721\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the pythagorean theorem to find the hypotenuse ER. \n" ); document.write( "(EA)^2 + (AR)^2 = (ER)^2 \n" ); document.write( "ER = sqrt( (EA)^2 + (AR)^2 ) \n" ); document.write( "ER = sqrt( (12.7279)^2 + (2.2721)^2 ) \n" ); document.write( "ER = 12.9291 \n" ); document.write( "Like the other decimal values, this is approximate.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another way to find segment ER is to use the Law of Cosines on triangle REB.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We have these key distances or segment lengths \n" ); document.write( "EB = 18 \n" ); document.write( "ER = 12.9291 (approx) \n" ); document.write( " \n" ); document.write( "Biff needs to travel 18 meters, and his speed is 1.5*1 = 1.5 m/s since it is 1.5 times faster compared to Rocco's speed (of 1 m/s).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Biff's travel time is: \n" ); document.write( "time = distance/rate \n" ); document.write( "time = EB/1.5 \n" ); document.write( "time = 18/1.5 \n" ); document.write( "time = 12 seconds\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Rocco needs to travel along segment ER = 12.9291, and his speed is 1 m/s, so, \n" ); document.write( "time = distance/rate \n" ); document.write( "time = ER/1 \n" ); document.write( "time = 12.9291/1 \n" ); document.write( "time = 12.9291\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We have these time values \n" ); document.write( "Biff = 12 seconds \n" ); document.write( "Rocco = 12.9291 seconds approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Because these time values are so close together, it's practically a tie.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we could only select one bear, then the winner is Biff \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The key assumption made is that each koala bear travels at their top speed right from the start. \n" ); document.write( "This is of course not realistic. \n" ); document.write( "The bears need time to build up to their top speed. \n" ); document.write( "There's no guarantee they maintain the top speed even after reaching it. \n" ); document.write( "The koalas also need to slow down when arriving at the eucalyptus, or else they would overshoot the goal.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For a more realistic way to solve this, we'd need to use a kinematic equation. However, such a topic is usually dealt with in physics classrooms. \n" ); document.write( " \n" ); document.write( " |