document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1204684>Question 1204684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mary’s age is 3 more than twice her brother’s age.  The sum of their ages is 33.  What is Mary’s age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #841099 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=841099\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mary’s age is 3 more than twice her brother’s age.\r<BR>\n" );
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document.write( "Let brother's age be x years\r<BR>\n" );
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document.write( "Mary's age will be (2x+3)\r<BR>\n" );
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document.write( "  The sum of their ages is 33.  What is Mary’s age?\r<BR>\n" );
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document.write( "x+2x+3=33\r<BR>\n" );
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document.write( "3x+3=33<BR>\n" );
document.write( "subtract 3 from both sides\r<BR>\n" );
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document.write( "3x=30<BR>\n" );
document.write( "divide by 3<BR>\n" );
document.write( "x=10\r<BR>\n" );
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document.write( "Brother's age = 10 years<BR>\n" );
document.write( "Mary's age = 2x+3 = 2(10)+3= 23 years\r<BR>\n" );
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document.write( " </SPAN>\n" );
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