document.write( "Question 1204672: The price p(in dollars) and the quantity x sold of a certain product obey the demand equation p=-1/5x+20 , 0<=p<=20
\n" ); document.write( "A.express the revenue R as a function of x
\n" ); document.write( "B. What is the revenue if 15 units are sold?
\n" ); document.write( "C.what quantity x maximizes revenue?
\n" ); document.write( "D. What price should the company charge to maximize revenue?
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The price p(in dollars) and the quantity x sold of a certain product obey the demand equation p=-1/5x+20 , 0<=p<=20
\n" ); document.write( "A.express the revenue R as a function of x\r
\n" ); document.write( "\n" ); document.write( "R= p*x\r
\n" ); document.write( "\n" ); document.write( "R= ((-1/5)x+20)*x\r
\n" ); document.write( "\n" ); document.write( "R = (-1/5)x^2+20x\r
\n" ); document.write( "\n" ); document.write( "B. What is the revenue if 15 units are sold?\r
\n" ); document.write( "\n" ); document.write( "R = (-1/5)x^2+20x\r
\n" ); document.write( "\n" ); document.write( "R= (-1/5)*15^2+20*15
\n" ); document.write( "R=$255\r
\n" ); document.write( "\n" ); document.write( "C.what quantity x maximizes revenue? \r
\n" ); document.write( "\n" ); document.write( "R = (-1/5)x^2+20x
\n" ); document.write( "dR/dx= -(2/5)*x+20
\n" ); document.write( "To maximise set the derivative to 0
\n" ); document.write( " -(2/5)*x+20=0
\n" ); document.write( "2/5*x=20
\n" ); document.write( "x=100/2
\n" ); document.write( "x= 50\r
\n" ); document.write( "\n" ); document.write( "D. What price should the company charge to maximize revenue?
\n" ); document.write( "Maximum units 50\r
\n" ); document.write( "\n" ); document.write( "P= -1/5*50+20
\n" ); document.write( "-10+20
\n" ); document.write( "=10
\n" ); document.write( "The company should charge $10 to maximize revenue when selling 50 units.\r
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