document.write( "Question 1204663: Two ships left a port at the same time. One ship traveled at a speed of 11 miles per hour at a heading of 320°. The other ship traveled at a speed of 23 miles per hour at a heading of 195°. Find the distance between the two ships after 10 hours of travel. (Round your answer to the nearest mile.) \n" ); document.write( "
Algebra.Com's Answer #841063 by avi2408(1) ![]() You can put this solution on YOUR website! \n" ); document.write( "From the diagram, we will use the cosine formula to find the distance between the two ships at 10 hours, i.e., BC. \n" ); document.write( "So, c^2=a^2+b^2-2abcosc \n" ); document.write( "c^2 = 110^2+230^2-2(110)(230)cos125 \n" ); document.write( "= 12100+52900+29022.9676=94022.9676. \n" ); document.write( "as c^2 = 94022.9676 \n" ); document.write( "c = sqrt(94022.9676) = 306.631 miles, or mi. \n" ); document.write( " |