document.write( "Question 1204663: Two ships left a port at the same time. One ship traveled at a speed of 11 miles per hour at a heading of 320°. The other ship traveled at a speed of 23 miles per hour at a heading of 195°. Find the distance between the two ships after 10 hours of travel. (Round your answer to the nearest mile.) \n" ); document.write( "
Algebra.Com's Answer #841063 by avi2408(1)\"\" \"About 
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\n" ); document.write( "From the diagram, we will use the cosine formula to find the distance between the two ships at 10 hours, i.e., BC.
\n" ); document.write( "So, c^2=a^2+b^2-2abcosc
\n" ); document.write( "c^2 = 110^2+230^2-2(110)(230)cos125
\n" ); document.write( "= 12100+52900+29022.9676=94022.9676.
\n" ); document.write( "as c^2 = 94022.9676
\n" ); document.write( "c = sqrt(94022.9676) = 306.631 miles, or mi.
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