document.write( "Question 1204654: For the ellipse, determine the
\n" ); document.write( "a) coordinates of the center
\n" ); document.write( "b) lengths of the major and minor axes
\n" ); document.write( "c) coordinates of the foci\r
\n" ); document.write( "\n" ); document.write( "9x^2 + 25y^2 - 9x - 50y - 197.75 = 0\r
\n" ); document.write( "\n" ); document.write( "------------
\n" ); document.write( "I did not get very far in this question. I was trying to first complete the square to factor into the standard form of the elliptical equation and move on from there.
\n" ); document.write( "9x^2 + 25y^2 - 9x - 50y - 197.75 = 0
\n" ); document.write( "9x^2 - 9x + 25y^2 - 50y = 197.75
\n" ); document.write( "9(x^2 - x) + 25(y^2 - 2y) = 197.75
\n" ); document.write( "9(x^2 - x + (1/4)) + 25(y^2 - 2y +1) = 197.75 + (1/4) + 1
\n" ); document.write( "9(x - (1/2))^2 + 25(y - 1)^2 = 199
\n" ); document.write( "I don’t know where to go from here because the numbers are troubling me
\n" ); document.write( "

Algebra.Com's Answer #841062 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "I appreciate that you've shown your work so far.
\n" ); document.write( "You're on the right track.
\n" ); document.write( "I'll start with the third step of your scratch work.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "9(x^2 - x) + 25(y^2 - 2y) = 197.75
\n" ); document.write( "9(x^2 - x + 0) + 25(y^2 - 2y + 0) = 197.75
\n" ); document.write( "9(x^2 - x + 0.25 - 0.25) + 25(y^2 - 2y + 1 - 1) = 197.75
\n" ); document.write( "9((x^2 - x + 0.25) - 0.25) + 25((y^2 - 2y + 1) - 1) = 197.75
\n" ); document.write( "9((x-0.5)^2 - 0.25) + 25((y-1)^2 - 1) = 197.75
\n" ); document.write( "9(x-0.5)^2 + 9(-0.25) + 25(y-1)^2 + 25(-1) = 197.75
\n" ); document.write( "9(x-0.5)^2 - 2.25 + 25(y-1)^2 - 25 = 197.75
\n" ); document.write( "9(x-0.5)^2 + 25(y-1)^2 - 27.25 = 197.75
\n" ); document.write( "9(x-0.5)^2 + 25(y-1)^2 = 197.75 + 27.25
\n" ); document.write( "9(x-0.5)^2 + 25(y-1)^2 = 225\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I'll let you finish up. The goal is to get the ellipse equation into the form \"%28%28x-h%29%5E2%29%2F%28a%5E2%29%2B%28%28y-k%29%5E2%29%2F%28b%5E2%29=1\"
\n" ); document.write( "(h,k) = center of the ellipse
\n" ); document.write( "a = half of the horizontal width
\n" ); document.write( "b = half of the vertical height
\n" ); document.write( "For example if a = 3 and b = 7 then the ellipse would be 2a = 2*3 = 6 units wide and 2b = 2*7 = 14 units tall.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In the steps where I've marked the terms in red, I'm completing the square.
\n" ); document.write( "For the (x^2-x) portion, the x coefficient is -1. That cuts in half to -0.5 and squares to 0.25
\n" ); document.write( "We add and subtract 0.25 to help complete the square for the x terms.
\n" ); document.write( "The y terms are the same idea: cut the y coefficient (-2) in half to get -1, then it squares to 1.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Use a graphing tool like GeoGebra or Desmos to check your answer.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If a > b, then the foci are located at (h-c, k) and (h+c, k) where,
\n" ); document.write( "c^2 = a^2 - b^2
\n" ); document.write( "OR
\n" ); document.write( "If b > a, then the foci are located at (h, k-c) and (h, k+c) where,
\n" ); document.write( "c^2 = b^2 - a^2
\n" ); document.write( "
\n" ); document.write( "
\n" );