document.write( "Question 1204657: The girl is 4 years older than her brother and 22 years younger than her father. Five years ago their father was twice as old as the sum of the ages of the children. How old is the children and father? \n" ); document.write( "
Algebra.Com's Answer #841060 by math_tutor2020(3816)\"\" \"About 
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\n" ); document.write( "x = brother's age 5 years ago
\n" ); document.write( "x+4 = sister's age 5 years ago
\n" ); document.write( "(x+4)+22 = x+26 = father's age 5 years ago\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Five years ago their father was twice as old as the sum of the ages of the children
\n" ); document.write( "father's past age = 2(brother's past age + sister's past age)
\n" ); document.write( "x+26 = 2(x + (x+4))
\n" ); document.write( "x+26 = 2(2x+4)
\n" ); document.write( "x+26 = 4x+8
\n" ); document.write( "26-8 = 4x-x
\n" ); document.write( "18 = 3x
\n" ); document.write( "3x = 18
\n" ); document.write( "x = 18/3
\n" ); document.write( "x = 6
\n" ); document.write( "x+4 = 6+4 = 10
\n" ); document.write( "x+26 = 6+26 = 32\r
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\n" ); document.write( "\n" ); document.write( "Five years ago the ages were
\n" ); document.write( "brother = 6
\n" ); document.write( "sister = 10
\n" ); document.write( "father = 32\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Add 5 to each of those values to get the present day ages.
\n" ); document.write( "6+5 = 11
\n" ); document.write( "10+5 = 15
\n" ); document.write( "32+5 = 37\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The present day ages are
\n" ); document.write( "brother = 11
\n" ); document.write( "sister = 15
\n" ); document.write( "father = 37
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