document.write( "Question 1204643: The denominator of a fraction is 7 more than the numerator. If both the numerator and the denominator are decreased by 2, the resulting fraction is equivalent to
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document.write( "6/13. Find the fraction. \n" );
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Algebra.Com's Answer #841033 by ikleyn(52814)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "The denominator of a fraction is 7 more than the numerator. If both the numerator and the denominator \n" ); document.write( "are decreased by 2, the resulting fraction is equivalent to 6/13. Find the fraction. \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let x be the numerator of the original fraction.\r\n" ); document.write( "Then the denominator is (x+7).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From the condition, we have this equation\r\n" ); document.write( "\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |