document.write( "Question 1204643: The denominator of a fraction is 7 more than the numerator. If both the numerator and the denominator are decreased by 2​, the resulting fraction is equivalent to
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Algebra.Com's Answer #841033 by ikleyn(52814)\"\" \"About 
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\n" ); document.write( "The denominator of a fraction is 7 more than the numerator. If both the numerator and the denominator
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document.write( "Let x be the numerator of the original fraction.\r\n" );
document.write( "Then the denominator is (x+7).\r\n" );
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document.write( "From the condition, we have this equation\r\n" );
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document.write( "    \"%28x-2%29%2F%28%28x%2B7%29-2%29\" = \"6%2F13\".\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    \"%28x-2%29%2F%28x%2B5%29\" = \"6%2F13\"\r\n" );
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document.write( "    13(x-2) = 6(x+5)\r\n" );
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document.write( "    13x - 26 = 6x + 30\r\n" );
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document.write( "    13x - 6x = 30 + 26\r\n" );
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document.write( "        7x   =   56.\r\n" );
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document.write( "         x   =   56/7 = 8.\r\n" );
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document.write( "ANSWER.  The fraction is  \"8%2F15\".\r\n" );
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