document.write( "Question 1204541: Carl bought a car for $5,000. The value of the car is decreasing by 9% each year. Janet bought a car for $3,000. The value of her car is decreasing by 3% per year. How long does it take for the value of the cars to be approximately the same? \n" ); document.write( "
Algebra.Com's Answer #841006 by MathTherapy(10552)\"\" \"About 
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document.write( "Carl bought a car for $5,000. The value of the car is decreasing by 9% each year. Janet bought a car for $3,000. The value of her car is decreasing by 3% per year. How long does it take for the value of the cars to be approximately the same?\r\n" );
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document.write( "He makes this problem so complex and still got the wrong answer. It's NOT 24 (\"highlight%28x=24%29\") years \r\n" );
document.write( "as he claims.\r\n" );
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document.write( "Let the number of years it takes for both cars to depreciate to the same amount, be y\r\n" );
document.write( "Then the yearly depreciation for the $5,000 car is, 5,000(1 - .09)y  \r\n" );
document.write( "And, the yearly depreciation for the $3,000 car is, 3,000(1 - .03)y\r\n" );
document.write( "We then set one equal to the other to get:  \r\n" );
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document.write( "                                                     \"matrix%281%2C3%2C+y%2C+%22=%22%2C+log+%28%28.91%2F.97%29%2C+3%2F5%29%29\" ---- Convert to logarithmic form\r\n" );
document.write( "Number of years it'll take for the value of the cars to be approximately the same, or y  = 8
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