document.write( "Question 1204625: Stacy loaned Juan $1040
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document.write( " at an interest rate of 15%
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document.write( " for 226
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document.write( " days. How much will Juan pay Stacy at the end of 226
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document.write( " days? Round your answer to the nearest cent. Note: Assume 360
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document.write( " days in a year and 30
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document.write( " days in a month.
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document.write( " \n" );
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Algebra.Com's Answer #840994 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Stacy loaned Juan $1040 \n" ); document.write( "at an interest rate of 15% \n" ); document.write( "for 226 days. How much will Juan pay Stacy at the end of 226 \n" ); document.write( "days? Round your answer to the nearest cent. Note: Assume 360 \n" ); document.write( "days in a year and 30 \n" ); document.write( "days in a month.\r \n" ); document.write( "\n" ); document.write( "SI = P*n*R\r \n" ); document.write( "\n" ); document.write( "SI is simple interest \n" ); document.write( "P is the principal \n" ); document.write( "n is the number of years \n" ); document.write( "r=15%=0.15\r \n" ); document.write( "\n" ); document.write( "SI= 1040*0.628*0.15 =97.97\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1040+97.97=1137.97\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, at the end of 226 days, Juan will pay Stacy approximately $1137.97\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |