document.write( "Question 1204625: Stacy loaned Juan $1040
\n" ); document.write( " at an interest rate of 15%
\n" ); document.write( " for 226
\n" ); document.write( " days. How much will Juan pay Stacy at the end of 226
\n" ); document.write( " days? Round your answer to the nearest cent. Note: Assume 360
\n" ); document.write( " days in a year and 30
\n" ); document.write( " days in a month.
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Algebra.Com's Answer #840994 by mananth(16946)\"\" \"About 
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Stacy loaned Juan $1040
\n" ); document.write( "at an interest rate of 15%
\n" ); document.write( "for 226 days. How much will Juan pay Stacy at the end of 226
\n" ); document.write( "days? Round your answer to the nearest cent. Note: Assume 360
\n" ); document.write( "days in a year and 30
\n" ); document.write( "days in a month.\r
\n" ); document.write( "\n" ); document.write( "SI = P*n*R\r
\n" ); document.write( "\n" ); document.write( "SI is simple interest
\n" ); document.write( "P is the principal
\n" ); document.write( "n is the number of years
\n" ); document.write( "r=15%=0.15\r
\n" ); document.write( "\n" ); document.write( "SI= 1040*0.628*0.15 =97.97\r
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\n" ); document.write( "\n" ); document.write( "1040+97.97=1137.97\r
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\n" ); document.write( "\n" ); document.write( "Therefore, at the end of 226 days, Juan will pay Stacy approximately $1137.97\r
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