document.write( "Question 1204614: nick is now 14 years older than his sister. six years ago nick was twice his sisters age now. find both ages now \n" ); document.write( "
Algebra.Com's Answer #840971 by math_tutor2020(3816)\"\" \"About 
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\n" ); document.write( "n = Nick's age right now
\n" ); document.write( "n-14 = his sister's age right now\r
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\n" ); document.write( "\n" ); document.write( "Six years ago, Nick was n-6 years old.
\n" ); document.write( "This is twice as much as his sister's current age.
\n" ); document.write( "Nick's past age = 2*(sister's current age)
\n" ); document.write( "n-6 = 2(n-14)
\n" ); document.write( "n-6 = 2n-28
\n" ); document.write( "n-2n = -28+6
\n" ); document.write( "-n = -22
\n" ); document.write( "n = 22
\n" ); document.write( "Nick is currently 22 years old
\n" ); document.write( "His sister is currently n-14 = 22-14 = 8 years old.\r
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\n" ); document.write( "\n" ); document.write( "Six years ago, Nick was 22-6 = 16, which is double that of 8.
\n" ); document.write( "This is how we can confirm the answer is correct.\r
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\n" ); document.write( "\n" ); document.write( "Answers:
\n" ); document.write( "Nick = 22 years old currently
\n" ); document.write( "Sister = 8 years old currently
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