document.write( "Question 1204615: Given that
\n" ); document.write( "sin(a) =
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\n" ); document.write( " with a and b both in the interval \r
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\n" ); document.write( " find the exact values of
\n" ); document.write( "sin(a + b)
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\n" ); document.write( "cos(a − b).
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Algebra.Com's Answer #840969 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Question: Given that sin(a) = 4/5 and cos(b) = -1/3, with a and b both in the interval [pi/2, pi], find the exact values of
\n" ); document.write( "sin(a+b)
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\n" ); document.write( "cos(a-b)\r
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\n" ); document.write( "\n" ); document.write( "The pythagorean trig identity is useful here.
\n" ); document.write( "\"sin%5E2%28x%29%2Bcos%5E2%28x%29+=+1\"
\n" ); document.write( "Use that identity to go from \"sin%28a%29+=+4%2F5\" to \"cos%28a%29+=+-3%2F5\"
\n" ); document.write( "Angle 'a' is in quadrant 2 where cosine is negative.
\n" ); document.write( "I'll leave the steps and scratch work for the student to do.\r
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\n" ); document.write( "\n" ); document.write( "If \"cos%28b%29+=+-1%2F3\", then \"sin%28b%29+=+%282%2Asqrt%282%29%29%2F3\" due to the pythagorean trig identity.
\n" ); document.write( "Sine is positive in quadrant Q2.\r
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\n" ); document.write( "\n" ); document.write( "We'll then turn to this identity
\n" ); document.write( "\"sin%28a%2Bb%29+=+sin%28a%29cos%28b%29%2Bcos%28a%29sin%28b%29\"
\n" ); document.write( "which leads to
\n" ); document.write( "\"sin%28a%2Bb%29+=+%284%2F5%29%28-1%2F3%29%2B%28-3%2F5%29%2A%28%282%2Asqrt%282%29%29%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"sin%28a%2Bb%29+=+%28-4-6%2Asqrt%282%29%29%2F15\"\r
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\n" ); document.write( "\n" ); document.write( "And,
\n" ); document.write( "\"cos%28a-b%29+=+cos%28a%29cos%28b%29%2Bsin%28a%29sin%28b%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28a-b%29+=+%28-3%2F5%29%2A%28-1%2F3%29%2B%284%2F5%29%2A%28%282%2Asqrt%282%29%29%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28a-b%29+=+%283%2B8%2Asqrt%282%29%29%2F15\"
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