document.write( "Question 1204602: A manufacturer knows that their items have a lengths that are skewed right, with a mean of 13.5 inches, and standard deviation of 3.4 inches.\r
\n" ); document.write( "\n" ); document.write( "If 46 items are chosen at random, what is the probability that their mean length is greater than 12.3 inches?
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Algebra.Com's Answer #840968 by MathLover1(20850)\"\" \"About 
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x̄ = \"12.3+\" => mean length\r
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\n" ); document.write( "population mean \"mu=+13.5+\"\r
\n" ); document.write( "\n" ); document.write( "standard deviation \"sigma=+3.4\"\r
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\n" ); document.write( "\n" ); document.write( " to find: \"P\"(x̄ > \"12.3\")\r
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\n" ); document.write( "\n" ); document.write( "z-statistic: (x̄ -\"mu\")/\"%28sigma%2Fsqrt%28n%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "compute z-statistic for x̄ = \"12.3+\"\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%2812.3+-+13.5%29%2F%283.4%2Fsqrt%2846%29%29+=+-2.393763523456\"\r
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\n" ); document.write( "\n" ); document.write( " \"P%28z+%3E+-2.393763523456%29+=++0.99166175\" =>\"99.166175\"% chance of the sample mean being greater than \"12.3+\"inches long\r
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