document.write( "Question 1204614: nick is now 14 years older than his sister. six years ago nick was twice his sisters age now. find both ages now \n" ); document.write( "
Algebra.Com's Answer #840965 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Nick, n \n" ); document.write( "Sister, x \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Six Years Ago: \n" ); document.write( "n-6 \n" ); document.write( "and \n" ); document.write( "x-6 \n" ); document.write( "- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Subtract. \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------------------------MISTAKES IN THIS WORK------------------------ \n" ); document.write( "Nick was x+8 when the time was 6 years ago, at which time sister was x-6. \n" ); document.write( "Nick will always stay 14 years older than sister.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |