document.write( "Question 1204614: nick is now 14 years older than his sister. six years ago nick was twice his sisters age now. find both ages now \n" ); document.write( "
Algebra.Com's Answer #840965 by josgarithmetic(39617)\"\" \"About 
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Nick, n
\n" ); document.write( "Sister, x
\n" ); document.write( "\"n-x=14\"\r
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\n" ); document.write( "\n" ); document.write( "Six Years Ago:
\n" ); document.write( "n-6
\n" ); document.write( "and
\n" ); document.write( "x-6
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\n" ); document.write( "\"n-6=2x\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28n-x=14%2Cn-6=2x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28n-x=14%2Cn-2x=6%29\"
\n" ); document.write( "Subtract.
\n" ); document.write( "\"highlight%28x=8%29\"
\n" ); document.write( "-
\n" ); document.write( "\"highlight%28n=22%29\"\r
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\n" ); document.write( "\n" ); document.write( "----------------------------------MISTAKES IN THIS WORK------------------------
\n" ); document.write( "Nick was x+8 when the time was 6 years ago, at which time sister was x-6.
\n" ); document.write( "Nick will always stay 14 years older than sister.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B8=2%28x-6%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B8=2x-12\"\r
\n" ); document.write( "\n" ); document.write( "\"8%2B12=x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=20\"\r
\n" ); document.write( "\n" ); document.write( "Sister is 20 now and Nick is 34 now.
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