document.write( "Question 1204593: Isabella is buying tickets to a concert. Adult tickets (x) cost $45 each and children tickets (y) cost $37 each. Isabella spent a total of $521 and purchased 3 more children tickets than adult tickets. Which is a viable solution for the system of equations? \n" ); document.write( "
Algebra.Com's Answer #840937 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Your question \"Which is a viable solution for the system of equations\" is very strange....

\n" ); document.write( "The \"viable solution\" to a system of equations is THE solution to that system of equations.

\n" ); document.write( "Presumably you were given some examples of systems of equations that might BE USED TO SOLVE the problem, and you were supposed to choose the one which was a valid setup. But in that case, for us to answer your question, you would have to show us those examples.

\n" ); document.write( "Without seeing those examples, the simplest set of equations is

\n" ); document.write( "(1) 45x+37y=521 (total cost of x tickets at $45 each and y tickets at $37 each is $521)
\n" ); document.write( "(2) y=x+3 (the number of children tickets is 3 more than the number of adult tickets)

\n" ); document.write( "As for the solution for the numbers of adult and children tickets, with the two equations in that form it seems substitution would be the most straightforward solution method:

\n" ); document.write( "45x+37(x+3)=521

\n" ); document.write( "and go from there.

\n" ); document.write( "For a quick informal solution (which is good mental exercise), you can do this:

\n" ); document.write( "The \"extra\" 3 children tickets cost 3($37) = $111, so the remaining tickets (equal numbers of adult and children tickets) cost $521-$111=$410. Since one adult ticket and one children ticket cost $45+$37 = $82, the number of each kind of ticket is $410/$82 = 5.

\n" ); document.write( "So she bought 5 adult tickets and 5+3 = 8 children tickets.

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