document.write( "Question 1204559: Determine the intervals you would check to see when \n" );
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Algebra.Com's Answer #840885 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(1) Observe that f(1)=0, so x=1 is one root. \n" ); document.write( "(2) Use synthetic division to find the remaining polynomial when the factor (x-1) is removed. \r\n" ); document.write( "\r\n" ); document.write( " 1 | 7 10 -11 -6\r\n" ); document.write( " | 7 17 6\r\n" ); document.write( " +-----------------\r\n" ); document.write( " 7 17 6 0 \n" ); document.write( "(3) Factor the remaining polynomial, \n" ); document.write( " \n" ); document.write( "The other two roots are x=-3/7 and x=-2. \n" ); document.write( "The roots (smallest to largest) are now -2, -3/7, and 1; the intervals you need to check are \n" ); document.write( "ANSWER: The intervals to check are (-infinity,-2), (-2,-3/7), (-3/7,1), and (1, infinity). \n" ); document.write( "In fact, you don't need to check all those intervals to find where the function value is negative. You know that, with a cubic polynomial with positive leading coefficient and three distinct roots, the function value will be negative on (-infinity,-2) and (-3/7,1). \n" ); document.write( " \n" ); document.write( " |