document.write( "Question 1204554: The sum of two numbers is 40.when 3odd number 1 over 4 times the larger number is subtracted from 5odd number 1 over 2 times the smaller,the difference is -25.find the two numbers \n" ); document.write( "
Algebra.Com's Answer #840874 by mananth(16946)![]() ![]() You can put this solution on YOUR website! The sum of two numbers is 40.when 3odd number 1 over 4 times the larger number is subtracted from 5odd number 1 over 2 times the smaller,the difference is -25.find the two numbers\r \n" ); document.write( "\n" ); document.write( "The equations as understood by me\r \n" ); document.write( "\n" ); document.write( "x+y =40----------------------------(1)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply by 4\r \n" ); document.write( "\n" ); document.write( "22x-13y=-100-------------------------(2)\r \n" ); document.write( "\n" ); document.write( "Multiply (1) by 13 and to (2)\r \n" ); document.write( "\n" ); document.write( "13x+13y = 520 \n" ); document.write( "22x-13y = -100 \n" ); document.write( "35x = 420 \n" ); document.write( "x= 12\r \n" ); document.write( "\n" ); document.write( "x+y =40 \n" ); document.write( "12+y=40\r \n" ); document.write( "\n" ); document.write( "y=28\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |