document.write( "Question 1204520: Suppose that the probability that a passenger will miss a flight is 0.0999. Airlines do not like flights with empty​ seats, but it is also not desirable to have overbooked flights because passengers must be​ \"bumped\" from the flight. Suppose that an airplane has a seating capacity of 57 passengers.
\n" ); document.write( "​(a) If 59 tickets are​ sold, what is the probability that 58 or 59 passengers show up for the flight resulting in an overbooked​ flight?
\n" ); document.write( "​(b) Suppose that 63 tickets are sold. What is the probability that a passenger will have to be​ \"bumped\"?
\n" ); document.write( "​(c) For a plane with seating capacity of 250 ​passengers, what is the largest number of tickets that can be sold to keep the probability of a passenger being​ \"bumped\" below 1​%?
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Algebra.Com's Answer #840833 by ikleyn(52864)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "Suppose that the probability that a passenger will miss a flight is 0.0999.
\n" ); document.write( "Airlines do not like flights with empty​ seats, but it is also not desirable
\n" ); document.write( "to have overbooked flights because passengers must be​ \"bumped\" from the flight.
\n" ); document.write( "Suppose that an airplane has a seating capacity of 57 passengers.
\n" ); document.write( "​(a) If 59 tickets are​ sold, what is the probability that 58 or 59 passengers show up
\n" ); document.write( "for the flight resulting in an overbooked​ flight?
\n" ); document.write( "​(b) Suppose that 63 tickets are sold. What is the probability that a passenger
\n" ); document.write( "will have to be​ \"bumped\"?
\n" ); document.write( "​(c) For a plane with seating capacity of 250 ​passengers, what is the largest number of tickets
\n" ); document.write( "that can be sold to keep the probability of a passenger being​ \"bumped\" below 1​%?
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document.write( "                 Question  (a)\r\n" );
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document.write( "It is a binomial experiment.\r\n" );
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document.write( "There are 59 potential passengers. The probability that every given passenger will show up is 1 - 0.0999 = 0.9001.\r\n" );
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document.write( "The events for individual passengers are INDEPENDENT.\r\n" );
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document.write( "The question is: find the probability that of 59 passengers that bought tickets, 58 or 59 will show up\r\n" );
document.write( "(it is the event \"the flight is overbooked\").\r\n" );
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document.write( "n = 59 (the number of trials);\r\n" );
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document.write( "p = 0.9001  (the probability of \"success\" to each individual trial);\r\n" );
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document.write( "k >= 58  (the event of overbooking flight).\r\n" );
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document.write( "P(n=59; p=0.9001; k>=58) = P(n=59; p=0.9001; k=58) + P(n=59; p=0.9001; k=59) = \"C%5B59%5D%5E58%2A0.9001%5E58%2A0.0999\" + \"C%5B59%5D%5E59%2A0.9001%5E59\" =\r\n" );
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document.write( "   = \"59%2A0.9001%5E58%2A0.0999+%2B+0.0999%5E59\" = 0.01316  (rounded).    ANSWER\r\n" );
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document.write( "                 Question  (b)\r\n" );
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document.write( "It is a binomial experiment very similar to part (a).\r\n" );
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document.write( "There are 63 potential passengers. The probability that every given passenger will show up is 1 - 0.0999 = 0.9001.\r\n" );
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document.write( "The events for individual passengers are INDEPENDENT.\r\n" );
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document.write( "The question is: find the probability that of 63 passengers that bought tickets, at least 58 will show up\r\n" );
document.write( "(it is the event \"the flight is overbooked\").\r\n" );
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document.write( "n = 63 (the number of trials);\r\n" );
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document.write( "p = 0.9001  (the probability of \"success\" to each individual trial);\r\n" );
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document.write( "k >= 58  (the event of overbooking flight).\r\n" );
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document.write( "We want to find the probability  P = P(n=63; p=0.9001; k>=58) \r\n" );
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document.write( "Go to web-site https://stattrek.com/online-calculator/binomial and use online (free of charge) calculator there.\r\n" );
document.write( "Its interface is very simple, so even a beginner student can easily work with it.\r\n" );
document.write( "It facilitates using  many-addend formula, so calculations are really easy and fast.\r\n" );
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document.write( "The ANSWER is\r\n" );
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document.write( "       P = P(n=63; p=0.9001; k>=58)  = 0.3893.   \r\n" );
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document.write( "Alternatively, you may use standard function binomcfd on your regular TI-83/84 calculator.\r\n" );
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document.write( "About this function and how to use it read from this web-page https://www.statology.org/binompdf-vs-binomcdf/\r\n" );
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document.write( "The regular calculator will provide the same answer.\r\n" );
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